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AJAX - 服务器 响应
tryjs_ajax_responsexml
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<!DOCTYPE html> <html> <body> <h2>The XMLHttpRequest Object</h2> <p id="demo"></p> <script> const xhttp = new XMLHttpRequest(); xhttp.onload = function() { const xmlDoc = this.responseXML; const x = xmlDoc.getElementsByTagName("ARTIST"); let txt = ""; for (let i = 0; i < x.length; i++) { txt = txt + x[i].childNodes[0].nodeValue + "<br>"; } document.getElementById("demo").innerHTML = txt; } xhttp.open("GET", "/demo/cd_catalog.xml"); xhttp.send(); </script> </body> </html>